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Divide 8x^3-4x^2+6x+7 by (x-1)
I did long division?
x goes in to 8x^3.. 8x^2
so it would be 8x^3-4x^2+6x+7 - 8x^3-8x^2 yes?
anyway I did the long division and got
(x-1)/8x^3-4x^2+6x+7 = 8x^2+4x+10 r17
How do I check this? :L Can I use f(x) somehow... thanks for your help :D
yes i got the same answer as you :)
you can check it by using the factor theorem where you would do f(1) and sub 1 into the initial equation as your x value. if you work that out it gives you the value of the remainder.
so you should get 8-4+6+7=17 so it is right :)
Thanks :) I got it now.. that was really helpful :D