Divide 8x^3-4x^2+6x+7 by (x-1)

I did long division?

x goes in to 8x^3.. 8x^2

so it would be 8x^3-4x^2+6x+7 - 8x^3-8x^2 yes?

anyway I did the long division and got

(x-1)/8x^3-4x^2+6x+7 = 8x^2+4x+10 r17

How do I check this? :L Can I use f(x) somehow... thanks for your help :D

Posted Wed 1st June, 2011 @ 21:07 by

Steven
yes i got the same answer as you :)

you can check it by using the factor theorem where you would do f(1) and sub 1 into the initial equation as your x value. if you work that out it gives you the value of the remainder.

so you should get 8-4+6+7=17 so it is right :)

Answered Wed 1st June, 2011 @ 22:47 by

Bethan Reeves
Thanks :) I got it now.. that was really helpful :D

Answered Thu 2nd June, 2011 @ 12:58 by

Steven