# Newton's Laws and Momentum

• Created by: Agata
• Created on: 24-02-16 16:03
• Newton's Laws  and Momentum
• Momentum
• LINEAR MOMENTUM: The mass of an object multiplied by its velocity. It is a VECTOR. (symbol: p , units kg*m/s).
• p = mv
• The reason for using the term linear momentum is that there is another term, angular momentum for objects rotating.
• Momentum  = force x distance= change in momentum        Ft=mv-mu        Unit: Ns          VECTOR
• WORKED EXAMPLE      A truck going north along a motorway has a mass of 4000 kg and a velocity of 18 m/s. A car also going north along the motorway, has a mass of 1400 kg and a velocity of 35 m/s .
• A) Calculate the kinetic energy of each vehicle.  ANSWER: Truck : 1/2 x 4000 x 18 ^2 = 648 000 J.   Car: 1/2 x 1400 x 35^2 = 857500.
• kinetic energy = 1/2 m v ^"
• C) Calculate the distance each vehicle takes to stop against retarding force of 7000N         ANSWER Truck: 18^2/( 2 x 1.75 ) = 92.6m       Car: 35^2 /(2 x 5.0) = 122.5m
• s=v^2/2a
• Kinetic Energy    K.E= force x distance = change in K.E   Fd=1/2mv^2- 1/2mu^2            Unit: Nm = J     SCALAR
• B) Calculate the momentum of each vehicle. ANSWER  Truck: 4000 x 18 = 72 000 due north          Car: 1400 x 35 = 49 000 due north.
• p=mv
• WORKED EXAMPLE      A truck going north along a motorway has a mass of 4000 kg and a velocity of 18 m/s. A car also going north along the motorway, has a mass of 1400 kg and a velocity of 35 m/s .
• A) Calculate the kinetic energy of each vehicle.  ANSWER: Truck : 1/2 x 4000 x 18 ^2 = 648 000 J.   Car: 1/2 x 1400 x 35^2 = 857500.
• kinetic energy = 1/2 m v ^"
• C) Calculate the distance each vehicle takes to stop against retarding force of 7000N         ANSWER Truck: 18^2/( 2 x 1.75 ) = 92.6m       Car: 35^2 /(2 x 5.0) = 122.5m
• s=v^2/2a
• D) Calculate the time each vehicle takes to stop against a retarding force of 7000N. ANSWER       Truck: 18/1.75=10.3s  Car: 35/5=7.0s
• t=v/a