Chemistry 1.1
- Created by: selen.
- Created on: 18-04-15 15:40
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- Chemistry 1.1
- Amount of substances
- 1 mol=amount of any substance w/ as many paricles at there are C (in 12g of C12)
- So 12g of C12 contains 6x10^23 atoms
- n
- m
- Mr
- m
- Avogadro constant is the number of atoms per mole of the carbon-12 isotope
- 1 mol=amount of any substance w/ as many paricles at there are C (in 12g of C12)
- Empirical Formula
- Answer: So for Mg &Br this would be MgBr2
- Step 3: this gives a ratio (e.g. 1:2)
- Step 2: ÷ by the smallest number
- Step 1: divide the mass or % given by the Ar
- Step 2: ÷ by the smallest number
- Step 3: this gives a ratio (e.g. 1:2)
- Answer: So for Mg &Br this would be MgBr2
- Gas volumes
- At RTP:
- One mole of gas molecules occupies 24dm3
- n
- v
- 24
- v
- n
- The vol/mol of gas molecules is 24dm3mol-1
- One mole of gas molecules occupies 24dm3
- At RTP:
- Moles and solutions
- c
- n
- v
- n
- c
- Acids and Bases
- All acids contain hydrogen
- Proton donor
- the H+ ion is responsible for all acid reactions
- H is always released
- Common bases are hydr/oxides or organic compounds called amines
- Proton acceptor
- everyday uses: Mg(OH)2 (indigestion) or Ca(OH)2 (for acid soil)
- Alkali's are more corrosive than acids
- dissolves in water to form OH¯(aq)
- All acids contain hydrogen
- Redox and Oxidation numbers
- Oxidation is loss of e¯
- Reduction is gain of e¯
- Disproprtionation reaction is where a species is oxidised and reduced
- Oxidation numbers
- Uncombined element = 0
- Combined O2 = -2
- Combined H2 = +1
- Simple ion = charge on ion
- Oxidation numbers
- Amount of substances
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