Calculations Involving Mass
- Created by: Ash Ketcham + Pikachu
- Created on: 22-01-17 17:42
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- Calculations Involving Mass
- Empirical Formula
- Empirical Formula is the simplified amount of number ratio of atoms in an equation.
- Example: Ethene has an empirical formula of CH2.
- Question: Find the Empirical Formula for Mg and O Where it has 6g of Magnesium and 4g of Oxygen.
- The mass of Magnesium is 6g and Oxygen is 4g
- The RAM for Magnesium is 24 and the RAM for Oxygen is 16
- We then divide the mass by the Relative Atomic Mass (RAM) so that will equal 0.25 for Mg and 0.25 for O
- Mg O mass: 6g 4g RAM 24 16 divide mass and RAM: 0.25 0.25 Ratio: 1 1 Answer: MgO
- The answer is MgO
- Question: Find the Empirical Formula for Mg and O Where it has 6g of Magnesium and 4g of Oxygen.
- The mass of Magnesium is 6g and Oxygen is 4g
- The RAM for Magnesium is 24 and the RAM for Oxygen is 16
- We then divide the mass by the Relative Atomic Mass (RAM) so that will equal 0.25 for Mg and 0.25 for O
- Mg O mass: 6g 4g RAM 24 16 divide mass and RAM: 0.25 0.25 Ratio: 1 1 Answer: MgO
- The answer is MgO
- Then we find the ratio so we divide the answer we got by the smallest number that goes into both of the number. So the ratio for Mg is 1 and O is 1
- The answer is MgO
- Mg O mass: 6g 4g RAM 24 16 divide mass and RAM: 0.25 0.25 Ratio: 1 1 Answer: MgO
- We then divide the mass by the Relative Atomic Mass (RAM) so that will equal 0.25 for Mg and 0.25 for O
- The RAM for Magnesium is 24 and the RAM for Oxygen is 16
- The mass of Magnesium is 6g and Oxygen is 4g
- Question: Find the Empirical Formula for Mg and O Where it has 6g of Magnesium and 4g of Oxygen.
- Then we find the ratio so we divide the answer we got by the smallest number that goes into both of the number. So the ratio for Mg is 1 and O is 1
- The answer is MgO
- Mg O mass: 6g 4g RAM 24 16 divide mass and RAM: 0.25 0.25 Ratio: 1 1 Answer: MgO
- We then divide the mass by the Relative Atomic Mass (RAM) so that will equal 0.25 for Mg and 0.25 for O
- The RAM for Magnesium is 24 and the RAM for Oxygen is 16
- The mass of Magnesium is 6g and Oxygen is 4g
- Molecular Formula
- Molecular Formula is the exact amount of atoms in an equation.
- Example: Ethene has a molecular formula of C2H4.
- To find the RFM of an equation, Find the RAM of each element and multiply the number by how many atoms their are
- E.g. The RFM for CO2 is 44. The RAM for C is 12 and we add that by 32 (The RAM for 2 oxygen)
- Moles
- Number of Moles = mass/RAM or RFM
- Empirical Formula
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