C4 Chemistry GCSE
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- Created on: 23-10-20 19:20
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- C4 Chemistry
- Relative masses and moles
- The relative mass of an element is the number in the top right of the box in the periodic table, e.g Carbons relative atomic mass is 12.
- PERCENTAGE YIELD Copper oxide reacts with sulfuric acid to make copper sulfate and water. In an experiment, 1.6 g of dry copper sulfate crystals are made. If the theoretical yield is 2.0 g, calculate the percentage yield of copper sulfate.actual yield = 1.6 gpercentage yield = 1.62.0 × 100percentage yield = 80%
- LIMITING REACTANT:You can work out which is the limiting reactant is by balancing out the equation. The limiting reactant is the reactant that is all used up. It sets a limit on how much product can be made.
- How much aluminium chloride is formed when 2.7 g of aluminium are reacted with 9.125 g of HCl?What mass of aluminium chloride is formed when 2.7g of aluminium are reacted with 9.125g of HCl? 2Al + 6HCl ? 2AlCl3 + 3H2 BASICALLY DO DETERMINE THE LIMITING REACTANT WE Calculate the moles of both the reactant and the product. There is 0.25 mol in Hcl. So the ratio of of Al and HCl is 3:1.(simplified). Hcl is the limiting reaction as ther is only 0.25 mol and it will run out first.
- Equations and calculations
- Balancing equations
- You use this to calculate the masses of reactants and products in chemical reactions
- 1.Balance the equation out
- 2. Find the relative formula or atomic masses of the reactant and the thing produced. (The top right number next to the element.)
- IMPORTANT EQUATION = MOLES= MASS÷ RELATIVE FORMULA/ATOMIC MASS
- 3. Find the amount of moles in the reactant as you have been given the mass and Relative formula/atomic mass
- 4. Now, your moles for the reactant acts as a multiplier. For example (completely innacurate), 2NaCl (reactant) makes 6BrBa, the ratio would be 2:6 (which simplifies to 1:3). So if i got 1 mol from 2NaCl (not true just eg), then you would times by 3 to get 3 mols for 6BrBa (not true)
- 5. Now that you have the amount of mols for the product, you refer back to the IMPORTANT EQUATION and re arrange it to find the mass of the product. Done!
- 4. Now, your moles for the reactant acts as a multiplier. For example (completely innacurate), 2NaCl (reactant) makes 6BrBa, the ratio would be 2:6 (which simplifies to 1:3). So if i got 1 mol from 2NaCl (not true just eg), then you would times by 3 to get 3 mols for 6BrBa (not true)
- 3. Find the amount of moles in the reactant as you have been given the mass and Relative formula/atomic mass
- Concentrations
- A solution forms when a solute dissolves in a solvent. The concentration of a solution is a measure of how 'crowded' the solute particles are. The more concentrated the solution, the more particles it contains in a given volume.
- CONCENTRATIONS ARE MEASURED IN G/DM3 (CUBEF)
- EQUATION: Concentration(g/dm3) = mass of solute (g) ÷ volume (dm3)
- CONCENTRATIONS ARE MEASURED IN G/DM3 (CUBEF)
- A solution forms when a solute dissolves in a solvent. The concentration of a solution is a measure of how 'crowded' the solute particles are. The more concentrated the solution, the more particles it contains in a given volume.
- Relative masses and moles
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